Jefferson (South Dakota, USA)
Jefferson
| Chalo | United States  | |
|---|---|---|
| Ili mu chigaŵa | • South Dakota • Union County | |
| Malo ghake | 42°36′16″N 96°33′46″W | |
| Population | 475 | |
| Number of households | 315±88 | |
| Water as percent of area | 0 % | |
| Elevation above sea level | 340 metre | |
| Area | 1.322134 km², 1.30379 km² | |
| Postal code | 57038 | |
| Per capita income | 30,765 United States dollar | |
| Local dialing code | 605 | |
Jefferson ni mzinda cha South Dakota kwa United States[1]. Lili na ŵanthu 475 (2020).[2]
Vilembo vifupi
[lembaso | kulemba source]- ↑ archINFORM (in German, English, French, Spanish, and Italian), OCLC 45382278, archINFORM location ID 30341, Wikidata Q265049, retrieved 6 Mpupulu 2018
- ↑ https://api.census.gov/data/2020/dec/pl?get=P1_001N%2CNAME&for=place%3A%2A&in=state%3A46